\(\int \frac {x^7}{(a+\frac {b}{x^3})^{3/2}} \, dx\) [2044]

   Optimal result
   Rubi [A] (verified)
   Mathematica [C] (verified)
   Maple [B] (verified)
   Fricas [F]
   Sympy [A] (verification not implemented)
   Maxima [F]
   Giac [F]
   Mupad [F(-1)]

Optimal result

Integrand size = 15, antiderivative size = 315 \[ \int \frac {x^7}{\left (a+\frac {b}{x^3}\right )^{3/2}} \, dx=\frac {1729 b^2 \sqrt {a+\frac {b}{x^3}} x^2}{960 a^4}-\frac {247 b \sqrt {a+\frac {b}{x^3}} x^5}{240 a^3}-\frac {2 x^8}{3 a \sqrt {a+\frac {b}{x^3}}}+\frac {19 \sqrt {a+\frac {b}{x^3}} x^8}{24 a^2}+\frac {1729 \sqrt {2+\sqrt {3}} b^{8/3} \left (\sqrt [3]{a}+\frac {\sqrt [3]{b}}{x}\right ) \sqrt {\frac {a^{2/3}+\frac {b^{2/3}}{x^2}-\frac {\sqrt [3]{a} \sqrt [3]{b}}{x}}{\left (\left (1+\sqrt {3}\right ) \sqrt [3]{a}+\frac {\sqrt [3]{b}}{x}\right )^2}} \operatorname {EllipticF}\left (\arcsin \left (\frac {\left (1-\sqrt {3}\right ) \sqrt [3]{a}+\frac {\sqrt [3]{b}}{x}}{\left (1+\sqrt {3}\right ) \sqrt [3]{a}+\frac {\sqrt [3]{b}}{x}}\right ),-7-4 \sqrt {3}\right )}{960 \sqrt [4]{3} a^4 \sqrt {a+\frac {b}{x^3}} \sqrt {\frac {\sqrt [3]{a} \left (\sqrt [3]{a}+\frac {\sqrt [3]{b}}{x}\right )}{\left (\left (1+\sqrt {3}\right ) \sqrt [3]{a}+\frac {\sqrt [3]{b}}{x}\right )^2}}} \]

[Out]

-2/3*x^8/a/(a+b/x^3)^(1/2)+1729/960*b^2*x^2*(a+b/x^3)^(1/2)/a^4-247/240*b*x^5*(a+b/x^3)^(1/2)/a^3+19/24*x^8*(a
+b/x^3)^(1/2)/a^2+1729/2880*b^(8/3)*(a^(1/3)+b^(1/3)/x)*EllipticF((b^(1/3)/x+a^(1/3)*(1-3^(1/2)))/(b^(1/3)/x+a
^(1/3)*(1+3^(1/2))),I*3^(1/2)+2*I)*(1/2*6^(1/2)+1/2*2^(1/2))*((a^(2/3)+b^(2/3)/x^2-a^(1/3)*b^(1/3)/x)/(b^(1/3)
/x+a^(1/3)*(1+3^(1/2)))^2)^(1/2)*3^(3/4)/a^4/(a+b/x^3)^(1/2)/(a^(1/3)*(a^(1/3)+b^(1/3)/x)/(b^(1/3)/x+a^(1/3)*(
1+3^(1/2)))^2)^(1/2)

Rubi [A] (verified)

Time = 0.14 (sec) , antiderivative size = 315, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.267, Rules used = {342, 296, 331, 224} \[ \int \frac {x^7}{\left (a+\frac {b}{x^3}\right )^{3/2}} \, dx=\frac {1729 b^2 x^2 \sqrt {a+\frac {b}{x^3}}}{960 a^4}-\frac {247 b x^5 \sqrt {a+\frac {b}{x^3}}}{240 a^3}+\frac {19 x^8 \sqrt {a+\frac {b}{x^3}}}{24 a^2}+\frac {1729 \sqrt {2+\sqrt {3}} b^{8/3} \left (\sqrt [3]{a}+\frac {\sqrt [3]{b}}{x}\right ) \sqrt {\frac {a^{2/3}-\frac {\sqrt [3]{a} \sqrt [3]{b}}{x}+\frac {b^{2/3}}{x^2}}{\left (\left (1+\sqrt {3}\right ) \sqrt [3]{a}+\frac {\sqrt [3]{b}}{x}\right )^2}} \operatorname {EllipticF}\left (\arcsin \left (\frac {\left (1-\sqrt {3}\right ) \sqrt [3]{a}+\frac {\sqrt [3]{b}}{x}}{\left (1+\sqrt {3}\right ) \sqrt [3]{a}+\frac {\sqrt [3]{b}}{x}}\right ),-7-4 \sqrt {3}\right )}{960 \sqrt [4]{3} a^4 \sqrt {a+\frac {b}{x^3}} \sqrt {\frac {\sqrt [3]{a} \left (\sqrt [3]{a}+\frac {\sqrt [3]{b}}{x}\right )}{\left (\left (1+\sqrt {3}\right ) \sqrt [3]{a}+\frac {\sqrt [3]{b}}{x}\right )^2}}}-\frac {2 x^8}{3 a \sqrt {a+\frac {b}{x^3}}} \]

[In]

Int[x^7/(a + b/x^3)^(3/2),x]

[Out]

(1729*b^2*Sqrt[a + b/x^3]*x^2)/(960*a^4) - (247*b*Sqrt[a + b/x^3]*x^5)/(240*a^3) - (2*x^8)/(3*a*Sqrt[a + b/x^3
]) + (19*Sqrt[a + b/x^3]*x^8)/(24*a^2) + (1729*Sqrt[2 + Sqrt[3]]*b^(8/3)*(a^(1/3) + b^(1/3)/x)*Sqrt[(a^(2/3) +
 b^(2/3)/x^2 - (a^(1/3)*b^(1/3))/x)/((1 + Sqrt[3])*a^(1/3) + b^(1/3)/x)^2]*EllipticF[ArcSin[((1 - Sqrt[3])*a^(
1/3) + b^(1/3)/x)/((1 + Sqrt[3])*a^(1/3) + b^(1/3)/x)], -7 - 4*Sqrt[3]])/(960*3^(1/4)*a^4*Sqrt[a + b/x^3]*Sqrt
[(a^(1/3)*(a^(1/3) + b^(1/3)/x))/((1 + Sqrt[3])*a^(1/3) + b^(1/3)/x)^2])

Rule 224

Int[1/Sqrt[(a_) + (b_.)*(x_)^3], x_Symbol] :> With[{r = Numer[Rt[b/a, 3]], s = Denom[Rt[b/a, 3]]}, Simp[2*Sqrt
[2 + Sqrt[3]]*(s + r*x)*(Sqrt[(s^2 - r*s*x + r^2*x^2)/((1 + Sqrt[3])*s + r*x)^2]/(3^(1/4)*r*Sqrt[a + b*x^3]*Sq
rt[s*((s + r*x)/((1 + Sqrt[3])*s + r*x)^2)]))*EllipticF[ArcSin[((1 - Sqrt[3])*s + r*x)/((1 + Sqrt[3])*s + r*x)
], -7 - 4*Sqrt[3]], x]] /; FreeQ[{a, b}, x] && PosQ[a]

Rule 296

Int[((c_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Simp[(-(c*x)^(m + 1))*((a + b*x^n)^(p + 1)/
(a*c*n*(p + 1))), x] + Dist[(m + n*(p + 1) + 1)/(a*n*(p + 1)), Int[(c*x)^m*(a + b*x^n)^(p + 1), x], x] /; Free
Q[{a, b, c, m}, x] && IGtQ[n, 0] && LtQ[p, -1] && IntBinomialQ[a, b, c, n, m, p, x]

Rule 331

Int[((c_.)*(x_))^(m_)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Simp[(c*x)^(m + 1)*((a + b*x^n)^(p + 1)/(a*c
*(m + 1))), x] - Dist[b*((m + n*(p + 1) + 1)/(a*c^n*(m + 1))), Int[(c*x)^(m + n)*(a + b*x^n)^p, x], x] /; Free
Q[{a, b, c, p}, x] && IGtQ[n, 0] && LtQ[m, -1] && IntBinomialQ[a, b, c, n, m, p, x]

Rule 342

Int[(x_)^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> -Subst[Int[(a + b/x^n)^p/x^(m + 2), x], x, 1/x] /;
FreeQ[{a, b, p}, x] && ILtQ[n, 0] && IntegerQ[m]

Rubi steps \begin{align*} \text {integral}& = -\text {Subst}\left (\int \frac {1}{x^9 \left (a+b x^3\right )^{3/2}} \, dx,x,\frac {1}{x}\right ) \\ & = -\frac {2 x^8}{3 a \sqrt {a+\frac {b}{x^3}}}-\frac {19 \text {Subst}\left (\int \frac {1}{x^9 \sqrt {a+b x^3}} \, dx,x,\frac {1}{x}\right )}{3 a} \\ & = -\frac {2 x^8}{3 a \sqrt {a+\frac {b}{x^3}}}+\frac {19 \sqrt {a+\frac {b}{x^3}} x^8}{24 a^2}+\frac {(247 b) \text {Subst}\left (\int \frac {1}{x^6 \sqrt {a+b x^3}} \, dx,x,\frac {1}{x}\right )}{48 a^2} \\ & = -\frac {247 b \sqrt {a+\frac {b}{x^3}} x^5}{240 a^3}-\frac {2 x^8}{3 a \sqrt {a+\frac {b}{x^3}}}+\frac {19 \sqrt {a+\frac {b}{x^3}} x^8}{24 a^2}-\frac {\left (1729 b^2\right ) \text {Subst}\left (\int \frac {1}{x^3 \sqrt {a+b x^3}} \, dx,x,\frac {1}{x}\right )}{480 a^3} \\ & = \frac {1729 b^2 \sqrt {a+\frac {b}{x^3}} x^2}{960 a^4}-\frac {247 b \sqrt {a+\frac {b}{x^3}} x^5}{240 a^3}-\frac {2 x^8}{3 a \sqrt {a+\frac {b}{x^3}}}+\frac {19 \sqrt {a+\frac {b}{x^3}} x^8}{24 a^2}+\frac {\left (1729 b^3\right ) \text {Subst}\left (\int \frac {1}{\sqrt {a+b x^3}} \, dx,x,\frac {1}{x}\right )}{1920 a^4} \\ & = \frac {1729 b^2 \sqrt {a+\frac {b}{x^3}} x^2}{960 a^4}-\frac {247 b \sqrt {a+\frac {b}{x^3}} x^5}{240 a^3}-\frac {2 x^8}{3 a \sqrt {a+\frac {b}{x^3}}}+\frac {19 \sqrt {a+\frac {b}{x^3}} x^8}{24 a^2}+\frac {1729 \sqrt {2+\sqrt {3}} b^{8/3} \left (\sqrt [3]{a}+\frac {\sqrt [3]{b}}{x}\right ) \sqrt {\frac {a^{2/3}+\frac {b^{2/3}}{x^2}-\frac {\sqrt [3]{a} \sqrt [3]{b}}{x}}{\left (\left (1+\sqrt {3}\right ) \sqrt [3]{a}+\frac {\sqrt [3]{b}}{x}\right )^2}} F\left (\sin ^{-1}\left (\frac {\left (1-\sqrt {3}\right ) \sqrt [3]{a}+\frac {\sqrt [3]{b}}{x}}{\left (1+\sqrt {3}\right ) \sqrt [3]{a}+\frac {\sqrt [3]{b}}{x}}\right )|-7-4 \sqrt {3}\right )}{960 \sqrt [4]{3} a^4 \sqrt {a+\frac {b}{x^3}} \sqrt {\frac {\sqrt [3]{a} \left (\sqrt [3]{a}+\frac {\sqrt [3]{b}}{x}\right )}{\left (\left (1+\sqrt {3}\right ) \sqrt [3]{a}+\frac {\sqrt [3]{b}}{x}\right )^2}}} \\ \end{align*}

Mathematica [C] (verified)

Result contains higher order function than in optimal. Order 5 vs. order 4 in optimal.

Time = 10.04 (sec) , antiderivative size = 91, normalized size of antiderivative = 0.29 \[ \int \frac {x^7}{\left (a+\frac {b}{x^3}\right )^{3/2}} \, dx=\frac {1729 b^3+741 a b^2 x^3-228 a^2 b x^6+120 a^3 x^9-1729 b^3 \sqrt {1+\frac {a x^3}{b}} \operatorname {Hypergeometric2F1}\left (\frac {1}{6},\frac {1}{2},\frac {7}{6},-\frac {a x^3}{b}\right )}{960 a^4 \sqrt {a+\frac {b}{x^3}} x} \]

[In]

Integrate[x^7/(a + b/x^3)^(3/2),x]

[Out]

(1729*b^3 + 741*a*b^2*x^3 - 228*a^2*b*x^6 + 120*a^3*x^9 - 1729*b^3*Sqrt[1 + (a*x^3)/b]*Hypergeometric2F1[1/6,
1/2, 7/6, -((a*x^3)/b)])/(960*a^4*Sqrt[a + b/x^3]*x)

Maple [B] (verified)

Both result and optimal contain complex but leaf count of result is larger than twice the leaf count of optimal. 1453 vs. \(2 (244 ) = 488\).

Time = 2.50 (sec) , antiderivative size = 1454, normalized size of antiderivative = 4.62

method result size
risch \(\text {Expression too large to display}\) \(1454\)
default \(\text {Expression too large to display}\) \(2540\)

[In]

int(x^7/(a+b/x^3)^(3/2),x,method=_RETURNVERBOSE)

[Out]

1/320*(40*a^2*x^6-116*a*b*x^3+363*b^2)/a^4/x*(a*x^3+b)/((a*x^3+b)/x^3)^(1/2)-1/640/a^4*b^3*(2006*(1/2/a*(-a^2*
b)^(1/3)-1/2*I*3^(1/2)/a*(-a^2*b)^(1/3))*((-3/2/a*(-a^2*b)^(1/3)+1/2*I*3^(1/2)/a*(-a^2*b)^(1/3))*x/(-1/2/a*(-a
^2*b)^(1/3)+1/2*I*3^(1/2)/a*(-a^2*b)^(1/3))/(x-1/a*(-a^2*b)^(1/3)))^(1/2)*(x-1/a*(-a^2*b)^(1/3))^2*(1/a*(-a^2*
b)^(1/3)*(x+1/2/a*(-a^2*b)^(1/3)+1/2*I*3^(1/2)/a*(-a^2*b)^(1/3))/(-1/2/a*(-a^2*b)^(1/3)-1/2*I*3^(1/2)/a*(-a^2*
b)^(1/3))/(x-1/a*(-a^2*b)^(1/3)))^(1/2)*(1/a*(-a^2*b)^(1/3)*(x+1/2/a*(-a^2*b)^(1/3)-1/2*I*3^(1/2)/a*(-a^2*b)^(
1/3))/(-1/2/a*(-a^2*b)^(1/3)+1/2*I*3^(1/2)/a*(-a^2*b)^(1/3))/(x-1/a*(-a^2*b)^(1/3)))^(1/2)/(-3/2/a*(-a^2*b)^(1
/3)+1/2*I*3^(1/2)/a*(-a^2*b)^(1/3))*a/(-a^2*b)^(1/3)/(a*x*(x-1/a*(-a^2*b)^(1/3))*(x+1/2/a*(-a^2*b)^(1/3)+1/2*I
*3^(1/2)/a*(-a^2*b)^(1/3))*(x+1/2/a*(-a^2*b)^(1/3)-1/2*I*3^(1/2)/a*(-a^2*b)^(1/3)))^(1/2)*EllipticF(((-3/2/a*(
-a^2*b)^(1/3)+1/2*I*3^(1/2)/a*(-a^2*b)^(1/3))*x/(-1/2/a*(-a^2*b)^(1/3)+1/2*I*3^(1/2)/a*(-a^2*b)^(1/3))/(x-1/a*
(-a^2*b)^(1/3)))^(1/2),((3/2/a*(-a^2*b)^(1/3)+1/2*I*3^(1/2)/a*(-a^2*b)^(1/3))*(1/2/a*(-a^2*b)^(1/3)-1/2*I*3^(1
/2)/a*(-a^2*b)^(1/3))/(1/2/a*(-a^2*b)^(1/3)+1/2*I*3^(1/2)/a*(-a^2*b)^(1/3))/(3/2/a*(-a^2*b)^(1/3)-1/2*I*3^(1/2
)/a*(-a^2*b)^(1/3)))^(1/2))-640*b*(2/3*x/b/((x^3+b/a)*a*x)^(1/2)+4/3/b*(1/2/a*(-a^2*b)^(1/3)-1/2*I*3^(1/2)/a*(
-a^2*b)^(1/3))*((-3/2/a*(-a^2*b)^(1/3)+1/2*I*3^(1/2)/a*(-a^2*b)^(1/3))*x/(-1/2/a*(-a^2*b)^(1/3)+1/2*I*3^(1/2)/
a*(-a^2*b)^(1/3))/(x-1/a*(-a^2*b)^(1/3)))^(1/2)*(x-1/a*(-a^2*b)^(1/3))^2*(1/a*(-a^2*b)^(1/3)*(x+1/2/a*(-a^2*b)
^(1/3)+1/2*I*3^(1/2)/a*(-a^2*b)^(1/3))/(-1/2/a*(-a^2*b)^(1/3)-1/2*I*3^(1/2)/a*(-a^2*b)^(1/3))/(x-1/a*(-a^2*b)^
(1/3)))^(1/2)*(1/a*(-a^2*b)^(1/3)*(x+1/2/a*(-a^2*b)^(1/3)-1/2*I*3^(1/2)/a*(-a^2*b)^(1/3))/(-1/2/a*(-a^2*b)^(1/
3)+1/2*I*3^(1/2)/a*(-a^2*b)^(1/3))/(x-1/a*(-a^2*b)^(1/3)))^(1/2)/(-3/2/a*(-a^2*b)^(1/3)+1/2*I*3^(1/2)/a*(-a^2*
b)^(1/3))*a/(-a^2*b)^(1/3)/(a*x*(x-1/a*(-a^2*b)^(1/3))*(x+1/2/a*(-a^2*b)^(1/3)+1/2*I*3^(1/2)/a*(-a^2*b)^(1/3))
*(x+1/2/a*(-a^2*b)^(1/3)-1/2*I*3^(1/2)/a*(-a^2*b)^(1/3)))^(1/2)*EllipticF(((-3/2/a*(-a^2*b)^(1/3)+1/2*I*3^(1/2
)/a*(-a^2*b)^(1/3))*x/(-1/2/a*(-a^2*b)^(1/3)+1/2*I*3^(1/2)/a*(-a^2*b)^(1/3))/(x-1/a*(-a^2*b)^(1/3)))^(1/2),((3
/2/a*(-a^2*b)^(1/3)+1/2*I*3^(1/2)/a*(-a^2*b)^(1/3))*(1/2/a*(-a^2*b)^(1/3)-1/2*I*3^(1/2)/a*(-a^2*b)^(1/3))/(1/2
/a*(-a^2*b)^(1/3)+1/2*I*3^(1/2)/a*(-a^2*b)^(1/3))/(3/2/a*(-a^2*b)^(1/3)-1/2*I*3^(1/2)/a*(-a^2*b)^(1/3)))^(1/2)
)))/x^2/((a*x^3+b)/x^3)^(1/2)*(x*(a*x^3+b))^(1/2)

Fricas [F]

\[ \int \frac {x^7}{\left (a+\frac {b}{x^3}\right )^{3/2}} \, dx=\int { \frac {x^{7}}{{\left (a + \frac {b}{x^{3}}\right )}^{\frac {3}{2}}} \,d x } \]

[In]

integrate(x^7/(a+b/x^3)^(3/2),x, algorithm="fricas")

[Out]

integral(x^13*sqrt((a*x^3 + b)/x^3)/(a^2*x^6 + 2*a*b*x^3 + b^2), x)

Sympy [A] (verification not implemented)

Time = 0.71 (sec) , antiderivative size = 46, normalized size of antiderivative = 0.15 \[ \int \frac {x^7}{\left (a+\frac {b}{x^3}\right )^{3/2}} \, dx=- \frac {x^{8} \Gamma \left (- \frac {8}{3}\right ) {{}_{2}F_{1}\left (\begin {matrix} - \frac {8}{3}, \frac {3}{2} \\ - \frac {5}{3} \end {matrix}\middle | {\frac {b e^{i \pi }}{a x^{3}}} \right )}}{3 a^{\frac {3}{2}} \Gamma \left (- \frac {5}{3}\right )} \]

[In]

integrate(x**7/(a+b/x**3)**(3/2),x)

[Out]

-x**8*gamma(-8/3)*hyper((-8/3, 3/2), (-5/3,), b*exp_polar(I*pi)/(a*x**3))/(3*a**(3/2)*gamma(-5/3))

Maxima [F]

\[ \int \frac {x^7}{\left (a+\frac {b}{x^3}\right )^{3/2}} \, dx=\int { \frac {x^{7}}{{\left (a + \frac {b}{x^{3}}\right )}^{\frac {3}{2}}} \,d x } \]

[In]

integrate(x^7/(a+b/x^3)^(3/2),x, algorithm="maxima")

[Out]

integrate(x^7/(a + b/x^3)^(3/2), x)

Giac [F]

\[ \int \frac {x^7}{\left (a+\frac {b}{x^3}\right )^{3/2}} \, dx=\int { \frac {x^{7}}{{\left (a + \frac {b}{x^{3}}\right )}^{\frac {3}{2}}} \,d x } \]

[In]

integrate(x^7/(a+b/x^3)^(3/2),x, algorithm="giac")

[Out]

integrate(x^7/(a + b/x^3)^(3/2), x)

Mupad [F(-1)]

Timed out. \[ \int \frac {x^7}{\left (a+\frac {b}{x^3}\right )^{3/2}} \, dx=\int \frac {x^7}{{\left (a+\frac {b}{x^3}\right )}^{3/2}} \,d x \]

[In]

int(x^7/(a + b/x^3)^(3/2),x)

[Out]

int(x^7/(a + b/x^3)^(3/2), x)